Actually, that should not work, it should give you an error. 

This should work:

SELECT `fkid`,max(`foo`) as foo,`bar` FROM `test2` GROUP BY `fkid`  ORDER BY 
`bar` ASC



Miguel Guirao wrote:
> select max(bar) from mytable where unique fkid order by bar asc
>
> as far as I remember!!
>
> -----Original Message-----
> From: Peter Beckman [mailto:[EMAIL PROTECTED]
> Sent: Lunes, 13 de Noviembre de 2006 04:59 p.m.
> To: PHP-DB Mailing List
> Subject: [PHP-DB] MySQL SQL Query Help
>
>
> I have a table:
>
> id fkid   foo    bar
> 1  1      345    yellow
> 2  1      34     red
> 3  2      3459   green
> 4  2      345    brown
>
> I want to select the largest value of "foo" for a unique fkid, and return
> bar, the results ordered by bar.  In this case, 345 is the largest value of
> foo for fkid 1, and 3459 is the largest for fkid 2.  "green" comes before
> "yellow."  My desired result set would be:
>
>      fkid   foo    bar
>      2      3459   green
>      1      345    yellow
>
> How would I write that in SQL?  fkid and foo are ints, bar is a varchar.
>
> Beckman
> ---------------------------------------------------------------------------
> Peter Beckman                                                  Internet Guy
> [EMAIL PROTECTED]                             http://www.purplecow.com/
> ---------------------------------------------------------------------------
>
>   

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