Hi,
I use somethin as
$sql = 'INSERT INTO `text` (`Field`) VALUES (''aaa'')';
Also, check things with var_dump, use mysql_error, echo $sql/$insert and
check whether the query is well formed.
my best
mario
On Sat, 2007-01-27 at 19:55 -0600, Alexander wrote:
> I fixed my code and it shows up fine now. It says it supposedly enters the
> data when I input the fields but when I check the MySQL database, the info
> isn't there.
>
> Here's the fixed code if you wish to test it:
>
> <html>
>
> <body>
>
> <?php
>
> function add_to_table( $picture, $thumbnail ) {
> $picture = mysql_real_escape_string($picture);
> $thumbnail = mysql_real_escape_string($thumbnail);
>
> $user = "user";
> $pass = "password";
> $database = "mydata";
>
> $link = mysql_connect("localhost", $user, $pass);
> if(!$link) {
> echo 'Error in linking';
> }
>
> $db = mysql_select_db($database, $link);
>
> $insert = 'INSERT INTO domains ( picture, thumbnail ) values(
> $picture, $thumbnail )';
> $indata = mysql_query( $insert, $link );
>
>
> }
>
> function write_form() {
> echo "<form method='post' action='{$_SERVER['PHP_SELF']}'>";
>
> echo "<p>Enter url of large picture: <input type='text'
> name='picture' />";
>
> echo "<p>Enter url of thumbnail: <input type='text'
> name='thumbnail' />";
>
> echo "<p><input type='submit' value='Add to Database' />";
>
> echo "</form>";
> }
>
> if ( !empty( $_REQUEST['picture'] ) && !empty(
> $_REQUEST['thumbnail'] ) ) {
> $input = add_to_table( $_REQUEST['picture'],
> $_REQUEST['thumbnail'] );
> if(!input) {
> echo 'Error\!';
> }
> else {
> echo 'Data enter successfully\!';
> $idreturn = mysql_insert_id($input);
> echo 'Image inserted to ID ' . $idreturn;
> }
> }
> else {
> write_form();
> }
>
> ?>
>
> </body>
>
> </html>
>
--
mario <[EMAIL PROTECTED]>
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