Peter Beckman wrote:

Because I'm trying to point out a problem with PHP, where setting a
 reference when the other side is undefined or not set, PHP creates a
 reference to a previously non-existent array item, just by setting a
 reference.  I don't think that should happen.

And? what's wrong with that. The reference can be used in the future - I think thats why it doesnt produce any error message.
ie.
$array=array("1"=>"a","3"=>"c");
$ref=&$array["2"];
$array["2"]="b";
echo($ref);


OKi98

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