You could always do something like:
while( $x = myql_fetch_array( $results ) ) {
list( $var1, $var2, $var3, ... ) = $x;
echo "<input name=storename type=text value=$var1>";
}
Chris Carter wrote:
> I am trying to fetch data through this code:
>
> My code:
> for($i=0;$i<mysql_num_rows($results);$i++)
> {
> $rows = mysql_fetch_array($results);
> echo '<div>' ;
> echo ' <div class="fieldrow">' ;
> echo ' ' ;
> echo ' <label for="storename">Store
> name:</label>' ;
> echo ' ' ;
> echo ' <input name="storename" type="text"
> maxlength="35" id="storename"
> class="regForm" disabled="disabled" value=$rows[0]></input>' ;
> echo ' </div>' ;
>
> The value option in the textfield is not fetching the data, neither is it
> throwing errors. However the same code works perfectly as suggested by one
> of expert Nabble users:
>
> Nabble code:
>
> for($i=0;$i<mysql_num_rows($results);$i++)
> {
> $rows = mysql_fetch_array($results);
> echo("<input name=\"input1\" type=\"text\"
> value=$rows[0]>");
> }
>
> Please help.
>
> Chris
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