You could always do something like:

while( $x = myql_fetch_array( $results ) ) {
 list( $var1, $var2, $var3, ... ) = $x;
 echo "<input name=storename type=text value=$var1>";
}

Chris Carter wrote:
> I am trying to fetch data through this code:
> 
> My code:
> for($i=0;$i<mysql_num_rows($results);$i++)
> {
>                       $rows = mysql_fetch_array($results);
>       echo '<div>' ;            
>       echo '                    <div class="fieldrow">' ;
>       echo '                          ' ;
>       echo '                          <label for="storename">Store 
> name:</label>' ;
>       echo '                          ' ;
>       echo '                          <input name="storename" type="text" 
> maxlength="35" id="storename"
> class="regForm" disabled="disabled" value=$rows[0]></input>' ;
>       echo '                    </div>' ;
> 
> The value option in the textfield is not fetching the data, neither is it
> throwing errors. However the same code works perfectly as suggested by one
> of expert Nabble users:
> 
> Nabble code:
> 
> for($i=0;$i<mysql_num_rows($results);$i++)
>                       {
>                       $rows = mysql_fetch_array($results);
>                       echo("<input name=\"input1\" type=\"text\" 
> value=$rows[0]>");
>                       }
> 
> Please help.
> 
> Chris

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