I'm assuming that you have the image uploaded into a directory on the
server.
All you need to do is have the html tags:
print "<img src='folderofsource/" . $image . "'>"
----- Original Message -----
From: "Chris Carter" <[EMAIL PROTECTED]>
To: <php-db@lists.php.net>
Sent: Thursday, October 11, 2007 10:16 AM
Subject: [PHP-DB] Is displaying image in php tough?
I am trying to fetch the image from the database image field.
Fetching it from
$image=mysql_result($result,$i,"image");
And displaying it with:
../stores-images/
I know it requires some if else or array to display. This is new for me.
Please help!
Chris
--
View this message in context:
http://www.nabble.com/Is-displaying-image-in-php-tough--tf4607902.html#a13158056
Sent from the Php - Database mailing list archive at Nabble.com.
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
