Hello guys,

Thanks to you all for your kind replies. I will try the steps and get back to you if I encounter more problems.


Fortuno, Adam wrote:

Ha, ha, ha! Thank you good friend. I did say I didn't try the code :-)

AF> Please note, I haven't tried this. It just seems plausible.

I apologize if I confused anyone. I just meant to show how the parameter could 
help retrieve a picture. I wasn't too concerned with the particulars. Hopefully 
the concept is sound. If not, please do flame my note so no one attempts it.

Be Well,

-----Original Message-----
From: Mattyasovszky Janos [mailto:m...@matya.hu] Sent: Monday, March 02, 2009 9:29 AM
To: php-db@lists.php.net
Subject: Re: [PHP-DB] Retrieving Image Location in MySQL

Fortuno, Adam írta:

                //Write a query to pull out the picture's path
                $sql = "SELECT path FROM Image WHERE ID = %s";

Sorry, but this won't work, since you don't map the value of the escaped $value to the %s, lets say with sprintf()...


Sashikanth Gurram
Graduate Research Assistant
Department of Civil and Environmental Engineering
Virginia Tech
Blacksburg, VA 24060, USA

PHP Database Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php

Reply via email to