Dear List -

I would like to have two(2) forms in one PHP script. I would like to have the forms appear sequentially; ie, that the first form would appear, the data would be entered, and then the second form would appear, the data would be entered, and the script would exit.


The code below displays both forms simultaneously. After the data is entered for the first form, the second form appears again. After the data is entered for the second form, the script displays the statement "" from the first form.

Would you please help me correct the script so that it will perform as required.

Thanks.

Here is the code:
============
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd";>
<!-- kitten.php  Two forms in one program -->

<html><body>
<?php
global $todo;

// if form not yet submitted
// display form
if ( isset($_POST['cat']) && $_POST['submit'] === 'Submit Ktten' )
        die();


if ( isset($_POST['submit']) && $_POST['submit'] === 'Submit' )
        agerdo();
else
{
        echo "<form method=\"post\">";
        echo "Enter your date of birth, in mm/dd/yyyy format: <br />";
        echo "<input type=\"text\" name=\"dob\" />";
        echo "<input type=\"submit\" name=\"submit\" value=\"Submit\" />";
        echo "</form>";
}


function agerdo()

{
          global $todo;
        //  echo $todo;
      // process form input
      // split date value into components
      $dateArr = explode('/', $_POST['dob']);

      // calculate timestamp corresponding to date value
      $dateTs = strtotime($_POST['dob']);

      // calculate timestamp corresponding to 'today'
      $now = strtotime('today');

      // check that the value entered is in the correct format
      if ( sizeof($dateArr) != 3 )

        die('ERROR: Please enter a valid date of birth');

      // check that the value entered is a valid date
      if ( !checkdate($dateArr[0], $dateArr[1], $dateArr[2]) )

        die('ERROR: Please enter a valid date of birth');


      // check that the date entered is earlier than 'today'
      if ( $dateTs >= $now )
        die('ERROR: Please enter a date of birth earlier than today');
      // calculate difference between date of birth and today in days
      // convert to years
      // convert remaining days to months
      // print output
      $ageDays = floor(($now - $dateTs) / 86400);
      $ageYears = floor($ageDays / 365);
      $ageMonths = floor(($ageDays - ($ageYears * 365)) / 30);
      echo "You are approximately $ageYears years and $ageMonths months old.";
}

if ( isset($_POST['submit']) && $_POST['submit'] === 'Submit Kitten' )
        catdo();
if ( !isset($_POST['cat'])) //&& $_POST['submit'] === 'Submit Kitten' )

{
echo <<<HTML
        <form method="post" onsubmit="catdo();">
        Enter your kitten's name: <br />
        <input type="text" name="cat" />
        <input type="submit" name="submit" value="Submit Kitten" />
        </form>
HTML;
}

function catdo()
{


        $name_cat = $_POST['cat'];
        echo "Your Kitten is $name_cat";
        exit();
}


?>

</body></html>
===========
Ethan

MySQL 5.1 PHP 5 Linux [Debian (sid)]


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