On 3/20/2013 8:43 AM, Toby Hart Dyke wrote:

You're right - you're pulling $file out of thin air. Once uploaded, the
file is stored in $_FILES['file']['tmp_name'], and you need to manually
read the data into $file yourself. Something like:



On 3/19/2013 8:15 PM, Ron Piggott wrote:
Hi All
I don’t understand how to save an image to a mySQL table based on the
following form. I am trying to do this using Prepared Statements.  All
the fields except the image file itself save in the database.  Right
now I have $file as the variable when binding the values.  What should
it be?  Ron

# bind variables

         $stmt->bindValue(':caption', 'Test Caption', PDO::PARAM_STR);
         $stmt->bindValue(':image_type', $_FILES["file"]["type"],
         $stmt->bindValue(':image_size', $_FILES["file"]["size"],
         $stmt->bindValue(':image_name', $_FILES["file"]["name"],
         $stmt->bindValue(':image', $file, PDO::PARAM_STR);

And in doing this your destination would then be the final resting place for the image(s), with the pointer to each stored in your table record for that image. :)

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