[PHP-DEV] PHP 4.0 Bug #8998 Updated: htmlspecialchars() DONT convert a string/array ONCE

[zak]

ID: 8998
Updated by: zak
Reported By: [EMAIL PROTECTED]
Status: Open
Bug Type: Strings related
Assigned To: 
Comments:

The code in your example does not work due to problems with your string quoting.

$foo = "<a href="foo">..</a>";
// This is not a valid string
// PHP generates a parse error after the 2nd quote


Try this code snippet and let me know if it works:

<pre>
<?php
$foo = '<a href="foo">..</a>'."\n";
$foo = htmlspecialchars($foo);

print $foo;
// Should output &lt;a href=&quot;foo&quot;&gt;..&lt;/a&gt;

$foo = '<a href="foo">..</a>'."\n";

print $foo;
// Should output <a href="foo">..</a>
?>


Previous Comments:
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[2001-01-30 07:12:39] [EMAIL PROTECTED]
ReEdit...
Please note:

$foo = "<a href="foo">..</a>";
$foo = htmlspecialchars($foo);

//now $foo is "& lt;a href="foo"& gt;..& lt;/a& gt;" 

$foo = "<a href="foo">..</a>";

//$foo is & lt;a href="foo"& gt;..& lt;/a& gt; 
//although $foo is filled with a new value, $foo converts the string!


---------------------------------------------------------------------------

[2001-01-30 07:10:04] [EMAIL PROTECTED]
Please note:

$foo = "<a href="foo">..</a>";
$foo = htmlspecialchars($foo);

//now $foo is "&lt;a href="foo"&gt..&lt;/a&gt" 

$foo = "<a href="foo">..</a>";

//$foo is &lt;a href="foo"&gt..&lt;/a&gt; 
//although $foo is filled with a new value, $foo converts the string!


//sorry, my english is too poor to explain more

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Full Bug description available at: http://bugs.php.net/?id=8998


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