ID: 9092
User Update by: [EMAIL PROTECTED]
Status: Open
Bug Type: Class/Object related
Description: variables-by-references in class constructor not working
hmm, i see your point.
is it possible to define a value that should be
passwd by reference as optional?
Previous Comments:
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[2001-02-03 18:09:28] [EMAIL PROTECTED]
This should not work - how can you pass a literal value by reference?
However, you are right about the error message - it does seem to be incorrect.
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[2001-02-03 17:53:52] [EMAIL PROTECTED]
This code snippet:
class test {
function test(&$test1=false) {
}
}
gives me
Parse error - parse error, expecting `')''
on the line with the constructor (function ...)
shouldn't this work (or at least return a useful error)?
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Full Bug description available at: http://bugs.php.net/?id=9092
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