ID: 9576
Updated by: stas
Reported By: [EMAIL PROTECTED]
Old-Status: Open
Status: Closed
Bug Type: Scripting Engine problem
Assigned To:
Comments:
echo is a statement, not a function, thus cannot be used in
an expression. You are right to use print.
Previous Comments:
---------------------------------------------------------------------------
[2001-03-06 07:09:01] [EMAIL PROTECTED]
Miner parser bug.
PHP4.0.4pl1 on my Linux (PHP is running as Apache 1.3.17 module) gives parse error
with following code.
<tr class=<?php ($i % 2) ? echo('even') : echo('odd') ?>>
This one works as expected
<tr class=<?php ($i % 2) ? print('even') : print('odd') ?>>
Hope this helps.
---
Yasuo Ohgaki
=== SOURCE BEGIN ====
<html>
<head>
<title>test</title>
<meta http-equiv="Content-Type" content="text/html; charset=EUC-JP">
<link rel="stylesheet" href="../lib/css/std.css">
<style type="text/css">
<!--
.odd { background: #CCCCFF}
.even { background: #CCCCCC}
-->
</style>
</head>
<body bgcolor="#FFFFFF">
<table width="80%" border="2" cellspacing="1" cellpadding="1">
<?php
for ($i = 0; $i < 100; $i++) { ?>
<!-- <tr class=<?php if ($i % 2 == 0) echo('even'); else echo('odd'); // OK?>> -->
<!-- <tr class=<?php ($i % 2) ? print('even') : print('odd'); // OK ?>> -->
<tr class=<?php ($i % 2) ? echo('even') : echo('odd'); // NOT OK ?>>
<td>@</td>
<td>@</td>
</tr>
<?php
} // END for( ) loop
?>
</table>
</body>
</html>
==== END SOURCE ====
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