ID: 8794
Updated by: stas
Old-Status: Open
Status: Closed
Bug Type: PCRE related
Assigned To: 

Manual says that the behaviour of preg_grep is exaclty what
it is. You can use each() or foreach() to go through the
array, count() is not sacred in any way (and also is slower
and error-prone, since nobody warrants you that array
elements are in sequential order). 

Previous Comments:

[2001-01-19 11:35:15] [EMAIL PROTECTED]
The behavior is inconsistent with expectations and breaks code.

In the example given count() returns 1, so loops attempting to access found elements 
won't work.

preg_grep() now determines and then discards indexes, forcing the caller
to reconstruct 'valid' indexes (using the count() of the original array and 
comparisons to "").

If this is the preferred approach I suggest returning an array of indexes, not a half 
baked array of strings.


[2001-01-19 09:01:51] [EMAIL PROTECTED]
Yes, preg_grep() was always supposed to return the results with their original keys 
but it wasn't until the behavior was fixed a little while ago.


[2001-01-18 20:27:48] [EMAIL PROTECTED]

# The behavior of preg_grep() changed, seems to be broken.
# Don't know if it is a preg_grep() change or a Zend hash change.
# Indexing bug is my guess, or RedHat 7.0.
# Or maybe by design (see NEWS)
# Here is a test case for reproduction.

# Set up an array of strings.
$a = array( "foo", "bar", "baz" );

# Display them all first, FYI.
for( $bug = 0; $bug < count( $a ); $bug++ )
        echo "test: ".$a[$bug]."<br>";

# This works as expected, [0] is result, [1] is whatever.
$b = preg_grep( "/^foo/", $a );
echo "try to find foo as [0]: ".$b[0]."   count=".count( $b )."<br>";
echo "try to find foo as [1]: ".$b[1]."   count=".count( $b )."<br>";

# This fails as unexpected, [0] is whatever, [1] is result????
$b = preg_grep( "/^bar/", $a );
echo "try to find bar as [0]: ".$b[0]."   count=".count( $b )."<br>";
echo "try to find bar as [1]: ".$b[1]."   count=".count( $b )."<br>";



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