ID: 8972
User Update by: [EMAIL PROTECTED]
Old-Status: Closed
Status: Open
Bug Type: Scripting Engine problem
Description: Referenced variables and unset()

Dosn't solve my problem and the fact, that PHPs behavior is unuseable doing the thing 
I need it for. I have been written
an ugly workarround in PHP to make PHP working like I would expect it to.

During this I found out some other things, so in my eyes it remains as a bug, cause

<?
function test(&$bla) {
   unset($bla['hugo']);
   $bla['hugo']=3;
}

$bla=Array(
        'hugo'=>1,
        'huba'=>2
        );

test($bla);

print_r($bla);

?>

works as expected (Array ( [huba] => 2 [hugo] => 3 ) - what was the *least* thing I 
expected). So PHP works not harmonious with referenced variables, which is really a 
thing I cannot use in any way and will by sure cause many unexpected bugs for other 
developers - even if they read the documented behaviour for references very carefully.

Please would you be so kind to change the state of this bug (sorry, it IS a bug) to 
closed when PHP solves this problem as nearly everybody would expect it to; cause 
otherwise there could be the danger, that there will be no chance to change PHPs 
behavior, cause everybody expect it to behave like the mentioned bug. :-)

If you don't agree with me, just read the user contributed notes for 'References 
Explained'.

Previous Comments:
---------------------------------------------------------------------------

[2001-03-06 08:12:11] [EMAIL PROTECTED]
No, it won't work that way (your first example). Unset
breaks the reference. Please read the "References explained"
part in the manual.

---------------------------------------------------------------------------

[2001-01-28 19:40:52] [EMAIL PROTECTED]
I found another bug (see id #8937) in connection with unset(). [Unset dosnīt work 
properly since august 1999]

<?

function test(&$bla) {
   unset($bla);
   $bla="huhu";
}

$bla="HIHI";

test($bla);

echo $bla;

?>

This will return "HIHI" instead of an expected "" or "huhu".

This bug exists cause unset() unsets the reference to $bla, not $bla itself. This also 
depends the GLOBAL-statement (see #8937)!

This is a bug, cause it is against the PHP-concept of making no big difference between 
reference and value
[ $bla=1; $hugo=&$bla; $hugo=2 is in the sight of $bla the same as $bla=1; $bla=2; ]

If I want to delete &$bla the correct expression is unset(&$bla). unset($bla) has 
always to delete the value
and all references to it. (that's just my opinion :-)

A fix of this bug will produce some compatibility problems with scripts, which has 
been written into PHP4 (cause the bug is very old).
But a fix should be done, cause many developers won't mind, that unseting a reference 
is in the sight of PHP a completly other thing than unseting a value.
There should be no/very less problems with upgrading PHP3-scripts.

PS: Just a small thought. In autumn last year I programmed constructs like the 
following
<?
$bla=array(1,array(1,array(1,2,3),3),3);
$ref=&$bla[2][2];
unset($ref);
?>
And I wondered, that this won't work as expected. Now I know why.
A correct solution would be to unset the inner array(1,2,3) and $ref... any other 
behaviour will break the mentioned handling of PHP.

Thougth 2:
<?
$bla="HIHI";
$ref=&$bla;
unset($ref);
$ref="huhu";
?>
What is the correct value of $bla. "" (empty) or "huhu"?


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Full Bug description available at: http://bugs.php.net/?id=8972


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