ID: 10389
User Update by: [EMAIL PROTECTED]
Old-Status: Feedback
Status: Open
Bug Type: MySQL related
Description: mysql_query(); returns an invalid result resource

I checked what you said with mysqladmin and mysql.  The
database "ue" does exist, as does the table "jobsc."  Thanks
for saying something about the table being empty, as it was.
I fixed this problem (I'd had it before, but i just did this new
script by itself to make sure) and added 1 entry to the table "jobsc."  PHP4 still 
returns the same warning as before on the
"SELECT * FROM jobsc"  and in the mysql console, executing
that instruction returns the one and only row in the table jobsc.

Previous Comments:

[2001-04-18 20:29:19] [EMAIL PROTECTED]
My would not return false.  It's been a long long day.

But it would return false if the table jobsc did not exist or the database ue did not 



[2001-04-18 20:26:15] [EMAIL PROTECTED]
Your query is not returning any rows, and as such mysql_query returns false.  False of 
course is not a valid mysql result and thus the "Warning".

If you are 100% certain the query returns results then that would be a problem, 
otherwise this is not a bug.

Please check this query from the mysql command line and reopen if there really is a 



[2001-04-18 19:45:58] [EMAIL PROTECTED]
Here is the code I am using that produces the error:

    $db = mysql_connect("localhost");
    mysql_select_db("ue", $db);
    $result = mysql_query("SELECT * FROM jobsc");
    $rows = mysql_num_rows($result);

on the last line is where the error is generated.  In
any browser, I see:

Warning: Supplied argument is not a valid MySQL result
resource ...

My setup contains apache 1.3.19 with the static PHP 4.0.4pl1
module compiled in.  My configure lines for PHP are:

./configure --with-apache=/home/apache_1.3.19

/usr/local/mysql is the install directory for mysql

That is all the information I believe I have, and I'm
relatively sure that PHP is not crashing, per say.


Full Bug description available at:

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