ID: 11063
User Update by: [EMAIL PROTECTED]
Status: Suspended
Bug Type: Feature/Change Request
Operating system: Windows NT 4.0 Build 1381
PHP Version: 4.0.4pl1
Description: $var = function_returning_array(args)[0]; doesn't work
I think that $var=(function_returning_array(args))[0]; should also work, but it does
not either.
The real problem here is that the [] operator works only on variables, not on general
expressions.
Just trying to make php more c-like in it's expression syntax.
Previous Comments:
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[2001-05-23 17:33:22] [EMAIL PROTECTED]
This syntax does not make sense at all (to me). It is not present in any language
AFAIK.
A function simply returns an array, and if you want to do something with that, do it
later.
However, it is a valid feature request, but I don't think it wil be implemented in
short time.
Changed type to Feature Request and status to Suspended.
Derick
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[2001-05-23 16:35:48] [EMAIL PROTECTED]
$var = function_returning_array(args)[0];
gives an error but
$var = function_returning_array(args);
$var=$var[0];
works fine. I think that either should work.
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Full Bug description available at: http://bugs.php.net/?id=11063
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