ID: 13940 Updated by: cnewbill Reported By: [EMAIL PROTECTED] Old Status: Bogus Status: Duplicate Bug Type: MySQL related Operating System: RedHat 7.1 PHP Version: 4.2.0-dev New Comment:
Ehh not bogus. Like you said is a dupe. Even though I reported it before 14137. Oh well, -Chris Previous Comments: ------------------------------------------------------------------------ [2001-11-20 18:42:25] [EMAIL PROTECTED] This is basically a dup of #14137, bogusifying this one. ------------------------------------------------------------------------ [2001-11-05 19:42:17] [EMAIL PROTECTED] I can already hear the lame 'expected behavior, use mysql_select_db() before each query, blah, blah' excuses coming, but... If you are able to set "properties" per connection resource, one would think that those "properties" stay with that connection resource and do not get overriden by setting "properties" for other connection resources. This implementation seems rather misleading. Not sure where to point the finger here, Zend Resource Management??? -Chris yes I am aware I copy+pasted passwords, they are changed , not that you can access that server anyways :) ------------------------------------------------------------------------ [2001-11-05 19:19:30] [EMAIL PROTECTED] I need multiple connections to the same MySQL server to two different databases and mysql_select_db() is not honoring the resource_identifier, it is using the one of that last connection opened. //script <?php // test mysql_select_db with two active connections $conn1 = mysql_connect("localhost", "root" ,"#rain!"); if (!$conn1) { print "Could not connect to server one\n"; } else { if (!mysql_select_db("st2", $conn1)) print "Could not select DB on server one ".mysql_error($conn1)."\n"; } $conn2 = mysql_connect("localhost", "root" ,"#rain!"); if (!$conn2) { print "Could not connect to server two\n"; } else { if (!mysql_select_db("commercesys", $conn2)) print "Could not select DB on server two ".mysql_error($conn2)."\n"; } if (!mysql_query("select * from user", $conn1)) { print "Could not issue query to conn1 ".mysql_error($conn1)."\n"; } if (!mysql_query("select * from customer", $conn2)) { print "Could not issue query to conn2 ".mysql_error($conn2)."\n"; } ?> OUTPUT: Could not issue query to conn1 Table 'commercesys.user' doesn't exist If you flip the connect blocks you get: Could not issue query to conn2 Table 'st2.customer' doesn't exist I'll look at the source, but this is not too cool. -Chris ------------------------------------------------------------------------ Edit this bug report at http://bugs.php.net/?id=13940&edit=1 -- PHP Development Mailing List <http://www.php.net/> To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]