ID: 15037
Updated by: yohgaki
Old Summary: something wrong with the operator '--'
Reported By: [EMAIL PROTECTED]
Old Status: Bogus
Status: Open
Old Bug Type: Math related
Bug Type: Scripting Engine problem
PHP Version: 4.0.6
New Comment:
It seems type jaggling problem to me.
AFAIK, PHP should convert type depends on the context.
for() is the exception? Then it should be explicitly documented.
Openned again to make this clear :)
Previous Comments:
------------------------------------------------------------------------
[2002-01-15 00:44:08] [EMAIL PROTECTED]
Interesting approach, but why do you quote 2.1 ? It says that $num is
the _string_ "2.1" and not the number 2.1. Just nuke the quoes for $num
= 2.1; and you're done.
------------------------------------------------------------------------
[2002-01-14 23:44:34] [EMAIL PROTECTED]
I run below on win2000:
<?
$j = 0;
$num = '2.1';
for ($i=$num;$i>1;$i--)
{
echo "i== $i<br>";
if ($j++ == 10)
break;
}
?>
but I get the output:
i== 2.1
i== 2.1
i== 2.1
i== 2.1
i== 2.1
i== 2.1
i== 2.1
i== 2.1
i== 2.1
i== 2.1
i== 2.1
I think something may be wrong with the operator '--'.Maybe I am
right.
Good lunk.
------------------------------------------------------------------------
Edit this bug report at http://bugs.php.net/?id=15037&edit=1
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