ID: 15268
Updated by: georg
Reported By: [EMAIL PROTECTED]
Old Status: Open
Status: Bogus
Bug Type: Arrays related
Operating System: window NT
PHP Version: 4.0.6
New Comment:
In your sample you removed 2nd dimensions from $e, not
first, so $e[1] is an empty array.
e.g. vardump($e):
array(2) { [0]=> array(2) { [0]=> string(3) "aaa" [1]=>
string(3) "bbb" } [1]=> array(0) { } }
To remove first dimension use unset($e[1])
Regards
Georg
Previous Comments:
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[2002-01-29 00:33:14] [EMAIL PROTECTED]
hello :
i have a problem on remove 2 dimension array in which the count of
array still is same as before the array was remove.
example:
$e[0][0] = "aaa";
$e[0][1] = "bbb";
$e[1][0] = "111";
$e[1][1] = "222";
count(array) is equal to 2, then i try to remove an element of that
array using unset :
unset($e[1][0]);
unset($e[1][1]);
then i try to retrieve the count of array again, the result should be
1, but what i get from it is the count of the array is still not
change, which it :
echo count($e); //result is 2
i have been try this for single dimension array, there is no such
problem on it, just the 2 dimension array will face this kind of
problem.
thank you !!
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Edit this bug report at http://bugs.php.net/?id=15268&edit=1
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