ID: 15468
Updated by: [EMAIL PROTECTED]
Reported By: [EMAIL PROTECTED]
Status: Bogus
Bug Type: Arrays related
Operating System: Linux d2 2.2.20-ow1-procmax-smp
PHP Version: 4.1.1
New Comment:
for [EMAIL PROTECTED]: Can you explain me your words:
Simple because 'ap' is NOT a key in the first case.
?????
Just don't know, what you mean...
Previous Comments:
------------------------------------------------------------------------
[2002-02-09 13:55:52] [EMAIL PROTECTED]
first case:
array(3) { [1]=> string(2) "ap" [2]=> string(2) "aa" [3]=> string(2)
"dd" }
second case:
array(3) { ["ap"]=> int(1) ["aa"]=> int(2) ["dd"]=> int(3) }
Why is this different? Shouldn't this be the same?
as Array() definition says:
Syntax "index => values", separated by commas, define index and values.
index may be of type string or numeric. When index is omitted, a
integer index is automatically generated, starting at 0. If index is an
integer, next generated index will be the biggest integer index + 1.
Note that when two identical index are defined, the last overwrite the
first.
So I have used in first case the Example 3. 1-based index with
array():
$firstquarter = array(1 => 'January', 'February', 'March');
I thing, that the second case definition is wrong and should return
error, but as I see, the function array_key_exists works with this...
I'm I mad or what???
------------------------------------------------------------------------
[2002-02-09 13:39:15] [EMAIL PROTECTED]
Simple because 'ap' is NOT a key in the first case. See yourself with
var_dump($pole); how the array looks like.
------------------------------------------------------------------------
[2002-02-09 13:20:25] [EMAIL PROTECTED]
Hello,
I'm trying function array_key_exists in this sample script, but doesn't
work:
<?
$a="ap";
$pole = array(1 => "ap", "aa", "dd");
if (array_key_exists($a, $pole)):
echo "The element is in the array";
endif;
?>
but when using:
$pole = array("ap" => 1, "aa" => 2, "dd" => 3);
it's working. Can somebody look at this problem?
Thanks,
Pavel Hrabal
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