Which version of PHP are you running? Versions before 4.1.0 don't have
the $_* variables. $_FILES may be an exception, it might be only
available in 4.2.0 and later, but I'm not sure about that.
Sander
On 2002.05.27 19:47 Daniel CAstro wrote:
> My code is much more extense than this, but I guess this is the source
> of my
> problem.
> "arquivo" is a member of a form, it is a file type, declared like
> <input
> type="file" name="arquivo">...
> I need to know if there is a file selected or not, that is the reason
> of the
> bug.
> When I run this code, through the form it does not print anything,
> even when
> I choose a file on the previous html (html with a form, with an action
> calling this script...) My version of PHP is 4.x
> <?php
> $nome = $_POST['nome'];
> $des = $_POST['des'];
> $eng = $_POST['eng'];
> $id = $_POST['id'];
> $tabela = $_POST['tabela'];
> $tabela_nova = $_POST['dd_tipo'];
> $arquivo = $_FILES['arquivo']['name'];
> //Conexao com BD...
> printf("%s",$arquivo);
> ?>
>
> Why it is happenig???
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