At 01:25 22-8-2002, Marcus B�rger wrote:
>At 00:56 22.08.2002, you wrote:
>>
>>Is this what you are looking for?
>>
>>#include <stdio.h>
>>
>>int main()
>>{
>> double f;
>> char *result;
>> size_t buf_len=1024;
>>
>> result = (char *) malloc(buf_len+1);
>> f = -.3333333333333333;
>> if(snprintf(result, buf_len, "Result is: %f and precision 12:
>> %.12f\n", f, f) < 1)
>> {
>> fprintf(stderr, "Error\n");
>> }
>> else
>> {
>> printf("%s", result);
>> }
>>}
>>
>>$ ./snprintf
>>Result is: -0.333333 and precision 12: -0.333333333333
>
>No there are more important issues in compliancy .
>Especially there are libraries out which do not check for the length
>parameter (i already have the code needed for that)
Ok.
>The code for you provided does not work because you only
>check for the number of characters written. Instead you must
>check for the '0' in front of the decimal point. E.g:
>
>char buf[10];
>if (strcmp("0.1", snprintf(buf, sizeof(buf), "%.f", .1))) ...
>
>Besides the return value is different in the libraries, too. Some return
>the length actually written but C99 requires to return the number of
>characters that could have been written if buffer was large enough.
Then this one is definetely not C99 compliant. Changed the test to:
#include <stdio.h>
int main()
{
char buf[5];
int written;
written = snprintf(buf, sizeof(buf), "%f", .111);
if (strcmp("0.1", buf)==0 && written == 6)
{
printf("OK\n");
}
else
{
printf("Not ok: %s (%i)\n", buf, written);
}
}
Result:
Not ok: 0.11 (5)
Additionally - with "%.f" it rounds to integer zero.
Result:
Not ok: 0 (1)
Met vriendelijke groeten / With kind regards,
Webmaster IDG.nl
Melvyn Sopacua
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