On Tue, Aug 27, 2002 at 06:39:57AM -0700, Brad LaFountain wrote:
> <?
> $ar = array("b" => 1, "blah" => 1);
> $a1 = array("b" => 1, "blah" => 2);
> var_dump(array_diff($ar, $a1));
> ?>
> array(0) {
> }I guess this may not be clear from documentation. array_diff() works with values. So it will return all values from first array that are not in the others. Since the value 1 is present in $a1, all elements of value 1 are removed from $ar in the returned array. Stig -- PHP Development Mailing List <http://www.php.net/> To unsubscribe, visit: http://www.php.net/unsub.php
