You should use zval_ptr_dtor() to dispose the old value. Note the old
value won't actually be freed as long as any reference to the variable is
alive.
for example,
zval *ary1, *ary2;
/* $ary1 = array(); */
ALLOC_INIT_ZVAL(ary1);
array_init(ary1);
/* $ary2 = array(); */
ALLOC_INIT_ZVAL(ary2);
array_init(ary2);
/* $ary1['key'] = 123; */
add_assoc_long_ex(ary1, "key", sizeof("key"), 123);
/* $ary2['key'] = 456; */
add_assoc_long_ex(ary2, "key", sizeof("key"), 456);
/* $ary1 = $ary2 */
zval_add_ref(ary2);
zval_ptr_dtor(&ary1);
ary1 = ary2;
Moriyoshi
"John Lim" <[EMAIL PROTECTED]> wrote:
> Hi,
>
> I'm porting some PHP code to C, and was hoping that someone can help me.
>
> I have 2 variables $oldarray and $newarray that both hold arrays and want
> to set
>
> $oldarray = $newarray;
>
> I suppose i have to dispose of $oldarray before i set it to $newarray. I'm
> not sure what is the best way, so i did this.
>
> zval **oldarray,*newarray;
>
> zval_add_ref(&newarray);
> convert_to_null_ex(oldarray);
> *oldarray = newarray;
>
> Would this work? Secondly is there a better way. Thanks again.
>
> John Lim
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