Try this:
echo "<br><br>...are you logged in: " . LoggedIn() . "<br><br>";
The reason it wasn't working is because it thought LoggedIn was a
variable and () was part of the echo statement.
"Karl J. Stubsjoen" wrote:
>
> Okay, what is wrong with this:
>
> echo "<br><br>...are you logged in: $LoggedIn()<br><br>";
> // outputs: ...are you logged in: ()
>
> Function is:
> function LoggedIn(){
> global $HTTP_POST_VARS
> if ($HTTP_POST_VARS["Login"] == "PHPIsCool")
> {return "YES";}
> else
> {return "NO";}
> }
>
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Shawn Blaylock, ClipperNet Software Engineer
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