At 12:31 PM 1/26/2001, Krznaric Michael wrote:
sorry - here you all go..
// number crunching time
$count++;
$time = date("Y-m-d H:i:s");
$result = mysql_query("INSERT INTO links (count) VALUES $count WHERE lid=$id");
echo $result;
> You need to be a little more specific about DB and problem type.
>You may have to commit the transaction if commit is not implict (ex Oracle).
>There could be many resons including your SQL statement.
>
>Mike
>
>-----Original Message-----
>From: Kurth Bemis [mailto:[EMAIL PROTECTED]]
>Sent: Friday, January 26, 2001 12:23 AM
>To: [EMAIL PROTECTED]
>Subject: [PHP] arg....
>
>
>i'm having a horrible time updating 2 fields in the same db. I don't get
>an error but the fields aren't updated....can anyone send me a snippet for
>the to learn from?
>
>~kurth
>
>
>--
>PHP General Mailing List (http://www.php.net/)
>To unsubscribe, e-mail: [EMAIL PROTECTED]
>For additional commands, e-mail: [EMAIL PROTECTED]
>To contact the list administrators, e-mail: [EMAIL PROTECTED]
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail: [EMAIL PROTECTED]
