Hehehe,
I searched around on PHP.net, and found this tidbit of information. It
sounds to me that list() is written to only accept the first two elements
from the each(). Please correct me if I am misinformed :-)
Cheers,
Jason
[EMAIL PROTECTED]
16-Feb-2000 03:41
Ok, for you folks who are learning this, here's something that should help
your comprehension of each(), because I bashed my brains for a while on this
one.
The first example indicates that each() spits out a 4-cell 1 dimensional
array. This is all fine and dandy until you get to the second example, where
that seems to be thrown out the window, because though each() is still
spitting out 4 array elements, the list() being used is set up to only
accept 2 values, as it's being executed with only wo variables in it!
For some folks, this might not be a problem, but I couldn't understand the
mismatch - why was it done, and where did the array go that each()
generated?? Well, upon executing that code, it turns out that the first two
array elements of the 4 element array that each() creates are assigned to
those two variables, and the last two array element values are just thrown
away - they're totally ignored. It's how PHP is written.
Now, why do that? Well, the example was definitely written more to show
folks how to use each() to make life much easier when dealing with a
particular operations array in PHP that a lot of people work with, but it
also has the side effect (which hopefully my little explaination has made
more palatable) of demonstrating how each() can act when being used with
other functions that don't necessarily want all of each()'s input.
""Jason Mowat"" <[EMAIL PROTECTED]> wrote in message
95rrbg$p3i$[EMAIL PROTECTED]">news:95rrbg$p3i$[EMAIL PROTECTED]...
> Greets,
>
> I have a quick question:
>
> $Array = array(
> "val1" => "Value 1",
> "val2" => "Value 2",
> "val3" => "Value 3"
> );
>
> while(list($a,$b,$c,$d) = each($Array)) {
> print "$a = $c and $b = $d <br>";
> }
>
> Doesn't the "each" construct return a 4 element array, where element 1's
> index is 0, element 2's index is 1, element 3's index is "key" and element
> 4's index is "value"? Now, if that is the case, the above should work,
> right? I should create a list containing $a, $b, $c and $d, where $a and
$c
> contain key information, and $b and $d contain value information? For
some
> reason, $c and $d are NULL...
>
> What am I missing here?
>
> Cheers,
> Jason
>
>
>
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