Re: [PHP] Using a variable in a variable

[Alexander Wagner]

Brandon Orther wrote:
> $test($i)text = "$i";
>       ^^----------------------I want this variable to get bigger

Try this:
$test{$i}text = $i;

(I'm not sure if this actually works)

or 

$varname = 'test'.$i.'text';
$$varname = $i;

regards
Wagner

-- 
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