RE: [PHP] parse error driving me nuts ...

[Andrew]

Jon, John, Ifrim, the == worked ... thank you!!
gotta read up on it now :)

Cameron, dropping the extra () did not work :(

thanks for the suggestions folks!
andrew


> -----Original Message-----
> From: Jon Haworth [mailto:[EMAIL PROTECTED]]
> Sent: Thursday, February 15, 2001 10:38 AM
> To: '[EMAIL PROTECTED]'; '[EMAIL PROTECTED]'
> Subject: RE: [PHP] parse error driving me nuts ...
> 
> 
> Instead of 
> 
> if ((mysql_num_rows($result)) = 1)
> 
> try
> 
> if ((mysql_num_rows($result)) == 1)
> 
> 
> HTH
> Jon
> 
> -----Original Message-----
> From: Andrew [mailto:[EMAIL PROTECTED]]
> Sent: 15 February 2001 15:34
> To: [EMAIL PROTECTED]
> Subject: [PHP] parse error driving me nuts ...
> 
> 
> hi, can anyone help me spot the parse error?
> It's throwing up on the first "if" line, and for the life of me I cannot
> find it! :)
> 
> tia,
> andrew
> 
> <?php
> 
> include("db_connect_params.inc");
> $sql="select path from PHOTO where pid =1";
> $link_id = mysql_connect($host, $usr, $pass);
> $result = mysql_db_query($database, $sql, $link_id) or die("no result");
> 
> if ((mysql_num_rows($result)) = 1)
> 
> {
>  $row=mysql_fetch_array($result);
>  extract($row);
>  echo "<img src =\"$path\"></img><br>";
> 
> } else {
>          if (!isset($ii)) $ii = 1;
>          $i = 1;
>          while($row=mysql_fetch_array($result))
>              {
>                 extract($row);
>                 $displayed[$i]=$path;
>                 echo "<a href=\"$PHP_SELF?ii=$i\">$i</a>&nbsp&nbsp";
>                 $i++;
>              }
>          echo "<img src =\"$displayed[$ii]\"></img><br>";
>         }
> ?>
> 
> 
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