i'd use split, to split the value up into an array:
if this is your url
$url = "/pages/error.php?/pages/login.php?user=scott";
and use this code:
$thing = split('\?', $url);
print $thing[0] ." <BR>\n ";
print $thing[1] ." <BR>\n ";
print $thing[2] ." <BR>\n ";
output will be:
/pages/error.php
/pages/login.php
user=scottx
----- Original Message -----
From: "James, Yz" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Friday, February 16, 2001 5:57 PM
Subject: [PHP] Finding the? in $REQUEST_URI?page=blah
> I really wouldn't ask this if I wasn't completely exausted, but the last
> thing I feel like doing just now is reading up on this when someone can
> probably answer it in a matter of seconds.....
>
> OK, I've an error handling page. Basically, I want to split (that might
> even be one of the functions I'll have to use) this sort of url:
>
> error.php?/pages/login.php?username=name
>
> into:
>
> /pages/login.php
>
> I'm using :
>
> header("location: error.php?page=$REQUEST_URI");
>
> When echoing the request_uri back on the error page, it omits the error.php?
> bit, so I get:
>
> login.php?username=name
>
> The reason I want to do this is so that I can use a re-login form that will
> submit to the page the user has badly logged into, so if they logged in to
> main.php, the request_uri would be something like:
>
> /pages/main.php?username=name
>
> Which I'd want to rebuild on the error page, into a form, like:
>
> <form method="post" action=<? echo "$REQUEST_URI"; /* Minus the suffix the
> page may include */ ?>">
> Username: <input type="text" name="username"><r>
> etc</form>
>
> Can anyone help?
>
> Thankees :)
>
> James.
>
>
>
>
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