<?
$otherDate = "2003-11-15"; // yyyy-mm-dd format
$otherDateStamp = strtotime($otherDate); // now a unix timestamp
$difference = time() - $otherDateStamp; // diff in seconds
?>
Then you need to decide if you want to show days, or hours, or years
difference...
I'll show you hours and days:
<?
$differenceHours = $difference / 3600; // 60secs x 60 mins
$differenceDays = $difference / 86400; // 60 x 60 x 24 hours
?>
You then need to round the number using round().
Justin
on 11/03/03 3:02 PM, Ben C. ([EMAIL PROTECTED]) wrote:
> There are a lot of artlicles on this but I need a simple solution. I need
> to subtract two dates as follows:
>
> $date = date("Y-m-d");
> $date1 = "2003-03-03";
> $differencedate = ($date - $date1);
> echo $differencedate;
>
> When I do this I get 0. Please help!
>
>
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