if ($num = 0)
{
echo "There are no matches for your search. Please try again.";
}
else
{
while ($row = mysql_fetch_array( $db_query ))
{
echo "<tr>
<td align=\"left\"><a href=\"editsoftwareasset.php?id=$row[asset_id]\">$row[asset_id]</a></td>
</td>
<td>$row[developer]
</td>
<td align=\"center\">$row[title]
</td>
<td align=\"center\">$row[version]
</td>
<td align=\"center\">$row[platform]
</td>
</tr>\n";
}
}
On Thursday, March 13, 2003, at 05:45 AM, Michael Roger C. Bianan wrote:
Mike,
Use mysql_num_rows($db_query) ;
- returns no of rows in the result set.
- if none, returns 0.
Thanks,
Miches
-----Original Message----- From: Mike Tuller [mailto:[EMAIL PROTECTED] Sent: Wednesday, March 12, 2003 11:17 AM To: php mailing list list Subject: [PHP] Check to see if mysql_fetch_array result is empty
How can I check to see if a mysql_fetch_array is empty. I have a search page, and want to have it so that when there are no matches, it returns a message saying that there were no matches, and if there are, then display them. Here is what I have so far to give you an idea as to what I am trying to do.
Thanks
-----------------
$query = "SELECT * FROM software_assets WHERE $searchType LIKE
'$search' ";
$db_query = mysql_query($query, $db_connect) or die (mysql_error());
while ($row = mysql_fetch_array( $db_query ))
{
if $row = NULL
{
echo "There were no results that match your query. Please try again";
}
else
{
echo "<tr>
<td align=\"left\"><a
href=\"editsoftwareasset.php?id=$row[asset_id]\">$row[asset_id]</a></ td>
</td>
<td>$row[developer]
</td>
<td align=\"center\">$row[title]
</td>
<td align=\"center\">$row[version]
</td>
<td align=\"center\">$row[platform]
</td>
</tr>\n";
}
}
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