Ok. I have it changed, but I have something wrong here, because when I there result is 0, it doesn't print out the message that I want. If I have it print out the result, it says 0. It has to be something simple, but I can't see what is wrong.

if ($num = 0)
{
echo "There are no matches for your search. Please try again.";
}
else
{

while ($row = mysql_fetch_array( $db_query ))
{

echo "<tr>
<td align=\"left\"><a href=\"editsoftwareasset.php?id=$row[asset_id]\">$row[asset_id]</a></td>
</td>
<td>$row[developer]
</td>
<td align=\"center\">$row[title]
</td>
<td align=\"center\">$row[version]
</td>
<td align=\"center\">$row[platform]
</td>
</tr>\n";
}
}



On Thursday, March 13, 2003, at 05:45 AM, Michael Roger C. Bianan wrote:


Mike,

Use mysql_num_rows($db_query) ;

- returns no of rows in the result set.

- if none, returns 0.

Thanks,

Miches

-----Original Message-----
From: Mike Tuller [mailto:[EMAIL PROTECTED]
Sent: Wednesday, March 12, 2003 11:17 AM
To: php mailing list list
Subject: [PHP] Check to see if mysql_fetch_array result is empty


How can I check to see if a mysql_fetch_array is empty. I have a search page, and want to have it so that when there are no matches, it returns a message saying that there were no matches, and if there are, then display them. Here is what I have so far to give you an idea as to what I am trying to do.

Thanks
-----------------
$query = "SELECT * FROM software_assets WHERE $searchType LIKE
'$search' ";
$db_query = mysql_query($query, $db_connect) or die (mysql_error());

while ($row = mysql_fetch_array( $db_query ))
{
if $row = NULL
{
echo "There were no results that match your query. Please try again";
}
else
{
echo "<tr>
<td align=\"left\"><a
href=\"editsoftwareasset.php?id=$row[asset_id]\">$row[asset_id]</a></ td>
</td>
<td>$row[developer]
</td>
<td align=\"center\">$row[title]
</td>
<td align=\"center\">$row[version]
</td>
<td align=\"center\">$row[platform]
</td>
</tr>\n";
}
}



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