Re: [PHP] regex

[Leif K-Brooks]

Whoops!  Try this:

preg_replace('|%INCLUDE_FILE\\[[^\\]]*\\]%|','',$final_footer);

Nate Sanden wrote:

Thanks! That worked almost. It removed everything except for the 2 %
signs.
How might I remove those as well?

"Leif K-Brooks" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
 

Try this (entirely untested!):
$final_footer =
preg_replace('%INCLUDE_FILE\\[[^\\]]*\\]%','',$final_footer);
Nate wrote:

   

hi,

i need to search $final_footer for a string such as
%INCLUDE_FILE[/path/to/file]% (where /path/to/file could be anything) and
delete it from the string. it being %INCLUDE_FILE[/path/to/file]% (not
     

just
 

/path/to/file)

im new to regexps but im guessing I should use preg_match for this?

Can someone give me a code example?

thanks much
Nate




     

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