Hello,
First you need to convert dates in timestamp:
int mktime ( int hour, int minute, int second, int month, int day, int year [, int
is_dst])
or
strtotime('YYYY-MM-DD');
(year-month-date; 4 digit year; month and date need to be with leading zero)
Then you can use function like DateDiff('yyyy', $date1, $date2);
/***
* Interval:
- yyyy Year
- q Quarter
- m Month
- y Day of year
- d Day
- w Weekday
- ww Week of year
- h Hour
- n Minute
- s Second
*/
function DateDiff($interval, $date1, $date2)
{
// get the number of seconds between the two dates
$timeDifference = $date2 - $date1;
$res = 0;
switch ($interval) {
case 'yyyy':
$diff = 0;
break;
case 'q':
$diff = 0;
break;
case 'm':
$diff = 0;
break;
case 'y':
$diff = 0;
break;
case 'd':
$diff = bcdiv($timeDifference, 86400, 0);
break;
case 'w':
$diff = bcdiv($timeDifference, 604800, 0);
break;
case 'ww':
$diff = 0;
break;
case 'h':
$diff = bcdiv($timeDifference, 3600, 0);
break;
case 'n':
$diff = bcdiv($timeDifference, 60, 0);
break;
case 's':
$diff = $timeDifference;
break;
default:
$diff = 0;
}
$res = $diff;
return $res;
}
________________________
Best regards,
Nenad Djordjevic mailto:[EMAIL PROTECTED]
Diyomi Soft
http://www.diyomisoft.com/
Tuesday, March 24, 1998, 2:44:12 AM, you wrote:
B2> Does any one know how to calculate the difference between two dates. I need
B2> to find out the age of a user to make sure they are over the age of 13. I
B2> have searched for hours on this and found nothing that will help.
B2> TIA
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