On Wednesday 26 March 2003 03:12, Verdon Vaillancourt wrote: > I've got a function (crude but works) that checks for a value in the url > and then I call an image based on that value. > > if (isset($_GET['menu'])) { > $img_pick = substr($_GET['menu'],0,1); > } else { $img_pick = "1"; } > > echo "<img src=\"/images/mast_$img_pick.jpg\">"; > > What I'd like to do is check the directory 'images' first to see if > 'mast_$img_pick.jpg' exists and if it doesn't, call a different image such > as 'mast_default.jpg'. I'm sure this isn't hard, I'm just not sure how to > start.
is_file() -- Jason Wong -> Gremlins Associates -> www.gremlins.biz Open Source Software Systems Integrators * Web Design & Hosting * Internet & Intranet Applications Development * ------------------------------------------ Search the list archives before you post http://marc.theaimsgroup.com/?l=php-general ------------------------------------------ /* Happiness is just an illusion, filled with sadness and confusion. */ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php