I mean than when you run PHP in CGI mode, PHP doesn´t read default php.ini
location. It first to look php in your actual path. An example...
ecazfe04:/home3/www# php -v
PHP 4.3.1 (cgi), Copyright (c) 1997-2002 The PHP Group
Zend Engine v1.3.0, Copyright (c) 1998-2002 Zend Technologies
ecazfe04:/home3/www# export REQUEST_METHOD="POST"
// Now we are in CGI mode as if it was called from Apache.
ecazfe04:/home3/www# export REDIRECT_STATUS="200"
// To avoid force-cgi-redirect
ecazfe04:/home3/www# php -v
Content-type: text/html
X-Powered-By: PHP/4.3.1
No input file specified.
// Ok, we are in CGI mode and it looks for a file.
/home3/www# cd <path_to_file>
/home3/www# php index.php
Everithings gos OK, except that if exists php.ini in <path_to_file> PHP
uses it. That overrides default compilation option. You can see it if you
use phpinfo() in 'index.php'.
I think this shouldn´t be the correct way of reading php.ini, but maybe
I´m wrong. Can anybody help me? I run a webserver (Apache+PHP) that hosts
some virtualhosts and I don´t won´t that my customers could use an alternate
php.ini.
PS: Sorry, I´m Spanish and I don´t know if my explanation is clear
enough.
José Luis Pérez Ruiz
Arrakis Servicios y Comunicaciones S.L.U.
Edificio Expo, C/ Inca Garcilaso s/n
Isla de la Cartuja
41092 Sevilla
Telefono: 955 550 509
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