Hi,
I'm trying to do the following.. When $stadpict is filled in it must display the
picture (only the path to the picture is stored in Mysql). But when the string
($stadpict) is empty then it must not display the picture (and also not display a box
with a red cross in it (can't display picture! ;>). The only thing i'm getting is an
error message...
Parse error: parse error, unexpected T_STRING, expecting ',' or ';'
Code;
<?
// includes
include("../conf/config.php");
// open database connection
$connection = mysql_connect($host, $user, $pass) or die ("Unable to connect!");
// select database
mysql_select_db($db) or die ("Unable to select database!");
$stedenid=$_GET['stedenid'];
// generate and execute query
$query2 = "SELECT stedenid, naamstad, stadomschrijvk, stadpict FROM steden WHERE
stedenid = $stedenid";
$result2 = mysql_query($query2) or die ("Error in query: $query2. " . mysql_error());
$row2 = mysql_fetch_object($result2);
if (mysql_num_rows($result2) > 0)
{
?>
<font class="bold"><? echo $row2->naamstad; ?> </font>
<br><br><? echo $row2->stadpict;
?>
</td>
</tr>
</table>
<table cellspacing="0" width="405" cellpadding="0" border="0">
<tr style="padding-top:10">
<td width="139" valign="top" style="padding-left:20">
<?
while($row->$stadpict > 0)
{
?>
<img src="../steden/images/<? echo $row->stadpict; ?>" border="0" width="108"
height="160" alt=""></td>
<?
}
?>
<td width="266" valign="top" style="padding-right:10;padding-left:10"><? echo
$row2->stadomschrijvk;
}
else
{
Echo Geen informatie beschikbaar;
}
?>
Thanks for helping me out!
Frank
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