Hi Hugh,

Thanks, so far so good... no error messages.  What next to get it to display
the total properly?

BTW, I changed "$SelectQuery" to "$TestSub" since "$SelectQuery" is used
repeatedly in this script, and I figured it might conflict if I didn't use
the "new Query" part.

Kurosh


-----Original Message-----
From: Hugh Danaher [mailto:[EMAIL PROTECTED] 
Sent: Tuesday, June 03, 2003 12:53 AM
To: Kurosh Burris
Cc: [EMAIL PROTECTED]
Subject: Re: [PHP] Supplied argument is not a valid MySQL result resource 


try something simpler and see if it passes:

$SelectQuery="SELECT SUM(GiftSubscriptions) AS GiftSubs FROM Registration";
$Result = mysql_query($SelectQuery) or die("Something died in here!
".mysql_error());

----- Original Message -----
From: "Kurosh Burris" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Monday, June 02, 2003 7:54 PM
Subject: [PHP] Supplied argument is not a valid MySQL result resource


> Hi Everyone,
>
> I'm trying to get a very simple "sum" of the values in an MySQL database
> field column.  I have very little experience with PHP and SQL, but I learn
> quickly.  :)  Our resident PHP expert who built the full script is really
> busy, so I've been trying to do this myself.  The farthest I could get
from
> just reading various posts in other forums was:
>
> $SelectQuery = new Query ("SELECT SUM(GiftSubscriptions) AS GiftSubs FROM
> Registration");
> $Result = mysql_query($SelectQuery);
> $Value = mysql_fetch_array($Result);
> echo $Value['GiftSubs'];
>
> However, I'm getting this error:
>
> Warning: mysql_fetch_array(): supplied argument is not a valid MySQL
result
> resource
>
> Can someone tell me what's wrong with this part of the code?
>
> Thanks,
> Kurosh
>
>
>
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