Oh, ok this is how i want to do it exactly :
------------ query.php
<?php
$query = "select * FROM `table` where id='$value' order by name";
?>
------------ parse.php
<?php
$fcontents = join('' , file('query.php'));
preg_match_all("/^('\$(.*)')/si", $fcontents,$matches);
print_r($matches)
?>
Thanks
"Chris Hayes" <[EMAIL PROTECTED]> a écrit dans le message de news:
[EMAIL PROTECTED]
> At 13:54 12-6-03, you wrote:
> >>I got a headache doing this, i need to get vars inside an sql query. For
> >>example :
> >>
> >>$query = "select * FROM `table` where id='$value' order by name";
> >>preg_match_all("/^('\$(.*)')/si", $query,$matches);
>
>
> >That doesn't work as the new string already is like "select * FROM
`table`
> >where id='2' order by name" assuming $value was 2...
>
> True, so try using
>
> $query = "select * FROM `table` where id='__VALUE__' order by name";
>
> if you insist on doing it this way.
>
> If you decide to keep trying with the $value, you need to know that
> variables inside "double quotes" are entered on the spot, while not so
with
> 'single quotes'.
>
>
> Also it is nice to know that the $ has a special position in
preg_matching,
> i kept this mail from a post from december in this list:
>
> > such as $, you must escape it twice. For example:
> >
> > $matchme = "\$example";
> > if (preg_match("/\$example/", $matchme)) {
> >
> > will not be matched because PHP interprets the \$ and passes it as $.
> > Instead, you must do this:
> >
> > if (preg_match("/\\\$example/", $matchme)) {
>
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