Re: [PHP] Pipe $var to a shell command

[Leif K-Brooks]

If $myoutput is "foo", it will attempt to get input from a file named 
"foo".  Use "command | $myoutput" instead.

Tim T wrote:

I have a mem var $myoutput I would like to pipe it to the input of a
shell_exec command.
I tried  shell_exec("command < $myoutput") however this is not quite right.
Anybody have any ideas??


 

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