preg_matchtry without backslashes.
$pattern = "/$search/i";
if (preg_match ($pattern, $date[$i]))
{
echo "$date[$i]<br />";
}
you don't need the .*? in your regex (either * or ? multiplier) as preg_match searches
for any occurance (not from begin ^ or to end $).
ciao SVEN
"Aaron Axelsen" <[EMAIL PROTECTED]> schrieb im Newsbeitrag news:[EMAIL PROTECTED]
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I am trying to code a search, and i need to get my matching
expression to work right. The user can enter a value swhich is
stored in the vraible $search.
What the below loop needs to do, is search each entry of the array
for any occurance of the $search string. If i hard code in the
string it works, but not when passed as a varaible. Is there
something I am missing? Do i need to convert the $search variable to
soetmhing?
if (preg_match ("/.*?\\\$search.*?/i",$date[$i])) {
print "$date[$i]<br>";
}
- ---
Aaron Axelsen
AIM: AAAK2
Email: [EMAIL PROTECTED]
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