On Mon, 7 Jul 2003 17:36:26 +0100, you wrote: >I want to write a function (as I have written in several other languages) that >obtains it's arguments dynamically (using func_get_arg()) and then assigns to that >argument. Think of the way that scanf() works -- that sort of thing. > >I have distilled what I want to do in the code below. foo adds 1 to all of it's >arguments. > >function foo () { > $count = func_num_args(); > for($i = 0; $i <= $count; $i++) { > $var = func_get_arg($i); > // The following line should do it, but throws a syntax error > &$var = $var + 1; > } >} > >$a = '1'; >$b = '2'; >$c = '3'; > >foo($a, $b, $c); > >What I am doing is quite different than the above (and more complex), but I will be >able >to achieve what I want if I can get the above to work.
Well.... this would work function foo () { $count = func_num_args(); for($i = 0; $i < $count; $i++) { $var = func_get_arg($i); $var = $var + 1; echo ($var); } } But I get the feeling you're trying to modify the elements in-place? Any particular reason? If it's because you want to return multiple values from the function, consider this: function foo () { $args = array(); for ($i = 0; $i < func_num_args(); $i++) { $args[] = func_get_arg($i); } $args = array_map (create_function ('$a','return($a+1);'), $args); return ($args); } list ($a, $b, $c) = foo(1, 2, 3); echo ("$a, $b, $c"); -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php