I think that is what he was meaning.
IT SHOULDN'T WORK THAT WAY, BUT IT DOES!!!
Re-Read his first email a little closer.
Jim Lucas
----- Original Message -----
From: "Michael Smith" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Friday, July 11, 2003 3:44 PM
Subject: Re: [PHP] Private and protected variables in PHP 5?
> Hey,
>
> private vars are not accessible that way. This is the way it works...
>
> private $var is only usable by the class. You can't access it through
> $object->var.
>
> protected $var is only usable by the class if it was called directly,
> but not by any objects that are classes that are extended from the base.
> Example:
>
> class Parent {
> protected $var = "test";
> function blah($somevar) {
> ...
> }
> }
>
> class Child extends Parent {
> ...
> }
>
> $parent = new Parent;
> print $parent->var; //ouputs "test"
> $child = new Child;
> print $child->var; //outputs nothing
>
> as you can see $var is only accessible by objects that are specifically
> Parents, not Children.
>
> public vars are accessible by the class itself, ($this->var), derived
> classes, and by $class->var.
>
> HTH,
> Cheers!
> -Michael
> Paul Hudson wrote:
> > All,
> >
> > I'm toying with the new stuff available in PHP 5 (latest CVS), but I've
hit a
> > brick wall: both private and protected don't seem to work as I'd expect
them
> > to.
> >
> > Here's an example script:
> >
> > <?php
> > class dog {
> > // declare two private variables
> > private $Name;
> > private $DogTag;
> >
> > public function bark() {
> > print "Woof!\n";
> > }
> > }
> >
> > // new class, for testing derived stuff
> > class poodle extends dog {
> > public function bark() {
> > print "Yip!\n";
> > }
> > }
> >
> > // I now create an instance of the
> > // derived class
> > $poppy = new poodle;
> >
> > // and set its private property
> > $poppy->Name = "Poppy";
> > print $poppy->Name;
> > ?>
> >
> > For some reason, that script works fine - PHP doesn't object to me
setting
> > private variables in the derived class. Yet if I use "$poppy = new
dog", the
> > script errors out as expected. It's almost like PHP inherits the member
> > variables, but not the attached access control.
> >
> > For protected, here's another script:
> >
> > <?php
> > class dog {
> > // this next function is protected
> > // viz, it should be available to dog
> > // and its children
> >
> > protected function bark() {
> > print "Woof!\n";
> > }
> > }
> >
> > class poodle extends dog {
> > // nothing happening here
> > }
> >
> > $mydog = new poodle;
> > // I now call the protected function
> > $mydog->bark();
> > ?>
> >
> > That script errors out saying that I can't call the protected function
bark -
> > surely, being protected, it should be available in the poodle class too?
> >
> > Of course, it might be that these two pieces of functionality are not
yet
> > implemented in PHP, or, more likely, that I'm just misinterpreting the
> > documentation! ;)
> >
> > If you have any insight, please CC me into your response to the list.
> >
> > Thanks,
> >
> >
> > Paul
> >
>
>
> --
> Pratt Museum IT Intern
> All programmers are playwrights and all computers are lousy actors.
>
>
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