"David Nicholson" <[EMAIL PROTECTED]> wrote in message

This is a reply to an e-mail that you wrote on Wed, 30 Jul 2003 at
19:18, lines prefixed by '>' were originally written by you.

> If I have:
> $firstdate = "2003-06-28";
> then how can I get $firstdate plus 4 days?
> Thanks!

+ (60*60*24*4));

Should do the trick, you can probably use strtotime instead of all
the substr()'s but at a guess I would expect the above to be quicker
(not that I have benchmarked it).



David's reply was spot on but I thought I'd break it down for you in case
you didn't understand...

$firstdate = "2003-06-28";

// Parse the date
list($year, $month, $day) = explode("-", $firstdate);

// Get the timestamp for this date..
$ts = mktime(0,0,0,$month,$day,$year);

// Add four days to timestamp..
$ts += 345600;

// Get year, month, day for new date..
$newdate = date("Y-m-d", $ts);

The only thing that I'm doing differntly is the way in which I'm parsing the
date.  I'm using the list()=explode() method as opposed to substr() becuase
this method is not prone to fail when values are not zero filled.

Good luck,

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