Not sure if you got a reply to this, but you need to make list an array. Use list[] in your form as the variable name, and then $_GET["list"] will be an array of your values.
--- Hank TT <[EMAIL PROTECTED]> wrote: > Given the following querystring generated by, for example, a > multi-select > form list (menu), the contents of $_GET['list'] is expected to be > an array > holding 3 elements: > > http://awebsite.net/formlist.php?list=2&list=3&list=99 > > Yet I only see the last value returned as a lone string. Is this > expected? > > Thanks. > > > > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > ===== Mark Weinstock [EMAIL PROTECTED] *************************************** You can't demand something as a "right" unless you are willing to fight to death to defend everyone else's right to the same thing. *************************************** __________________________________ Do you Yahoo!? Yahoo! SiteBuilder - Free, easy-to-use web site design software http://sitebuilder.yahoo.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
