* Thus wrote Steven Kallstrom ([EMAIL PROTECTED]):
> Hello all...
>
> I'm embarrassed by this one... I think it should work but it isn't...
>
> $query = 'SELECT * FROM cities';
> $result = mysql_query($query);
>
> while ($row = mysql_fetch_row($result)) {
>
> getting this error:
>
> *Warning*: mysql_fetch_row(): supplied argument is not a valid MySQL
> result resource in...
Hmm.. I thought I had replied to this.. anyway, check the output of
mysql_error() after your mysql_query(), mysql_select_db() and
mysql_connect() to see who is cause the query to fail. The sql
syntax appears to be correct.
Curt
--
"I used to think I was indecisive, but now I'm not so sure."
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