[snip]
:) Tried that:
[/snip]

Let's be more verbose and see what happens....

if(!($myconnection = mysql_pconnect($server,$user,$pass))){
        print("Failed to connect to database!\n");
        exit();
        }
if(!mysql_select_db($db,$myconnection)){
        print("Failed to select database!\n");
        exit();
        }

$query = "select StudentId from" . $table . "where StudentID = '" .
$StudentID . "' ";
if(!($news = mysql_query($query, $myconnection))){
    print("ERROR! " . mysql_error() . "\n");
    exit();
}

$howmany = mysql_num_rows($news);
echo "$howmany \n";

if ($howmany == 1){
    include ("/the/full/path/to/html/access_error.htm");
} else {
    include ("/the/full/path/to/html/registration.htm");
}

It is my guess that your query is failing, so $news is not a valid
resource. Anytime you do a query you should also do a mysql_error()
statement so that a better clue might be printed out.

--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php

Reply via email to