> Warning: Unable to jump to row 0 on MySQL result index 2 in
> /home/sites/site3/web/showthumb on line 71
>
> --here is my code
Change it to look like this:
> $connetion = mysql_connect("localhost","cel34243","s2343223") or
die($php_errormsg);
> $query = "select images from celeb where name=\"$dir.\" ";
> $result = mysql_db_query("celebzone", $query) or die(mysql_error());
> $imagesnum= mysql_result($result, "images");
You are missing an argument there...
You need a row number in front of "images".
Also, you probably don't have any rows that matched your criteria, so asking
for the first row (row 0) is bad.
--
Visit the Zend Store at http://www.zend.com/store/
Wanna help me out? Like Music? Buy a CD: http://l-i-e.com/artists.htm
Volunteer a little time: http://chatmusic.com/volunteer.htm
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail: [EMAIL PROTECTED]
