OH! Heh... learn something new everyday.. Thank you! -Dan Joseph
> -----Original Message----- > From: Mike Migurski [mailto:[EMAIL PROTECTED] > Sent: Wednesday, October 01, 2003 3:49 PM > To: Dan Joseph > Cc: [EMAIL PROTECTED] > Subject: Re: [PHP] printf.... > > > >Warning: printf(): too few arguments in > >/home/sites/site8/web/index_test.php on line 34 > > > >I cannot for the life of me figure out what the problem is. I've looked > >thru archives, examples, and pages of a book all about printf, and this > >just doesn't add up to me.. Anyone see the problem? > > To print a literal '%' (as in '100%'), you need to escape it with another > '%' (as in '100%%'). > > --------------------------------------------------------------------- > michal migurski- contact info and pgp key: > sf/ca http://mike.teczno.com/contact.html > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
