Seeing as how you haven't had a response yet, I'll ask this: what exactly is your question? I'm not sure as to what it is that you want.
My question are:
a) Why does the PHP manual say that backslashes get escaped by writing them twice while this causes an error in my example (see below)?
b) Why does a different input (2.1. and 2.2.) result in the same output (in the example I enclosed)?
c) Why do I hate regular expressions so much?
Choose one.
- Jns
8<
1. The PHP manual sais to escape the escape char, it has to be written twice*, but:
$term = preg_replace('/(\\)/', 'backslash $1', $term);
causes an error** while using three backslashes (see 2.) works.
2.1. $term = "beg \ end"; print preg_replace('/(\\\)/', 'backslash $1', $term); returns: beg backslash \ end
2.2. $term = "beg \\ end"; print preg_replace('/(\\\)/', 'backslash $1', $term); returns: beg backslash \ end (the same as 2.1.)
2.3. $term = "beg \\\ end"; print preg_replace('/(\\\)/', 'backslash $1', $term); returns: beg backslash \backslash \ end
* http://www.php.net/manual/en/pcre.pattern.syntax.php
** "Warning: Compilation failed: missing ) at offset 3 in /home/jonas/public_html/test01.php on line 3"
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