Dont apologize. even the best of us make mistakes.
the .$field. is a more reliable way of displaying the information contained
within. as in a few cases I find the variable itself gets printed ie $field
shows up as $field in cases where I didnt use the .$field. just an
observation on my part.
if the form name was a typo then you will want to check your
register_globals in your php.ini file it probably is turned off
in which case you want to use
$l_name = $_POST["l_name"];
etc..
this will give you the var values with out having to change your php.ini
its also more secure if what I read is correct.
Chris
> I am LD. I do have the <? echo ?> in my code. The leads_id is an
> autonumber, it the primary key for the table. What do the .$field. gives
> you over $field?
> Also another LD mistake, addlead.php is addlead.php.
>
> I will try it.
>
> Payne
>
> Chris Sherwood wrote:
>
> >Hi Payne
> >
> >for starters your missing an ? at the last echo
> ><? echo $l_name>
> >
> >secondly I would rewrite the sql statement to read
> >$sql = "INSERT INTO $table_name
> > (leads_id, title, f_name, l_name)
> > VALUES
> > (' ".$leads_id." ', ' ".$title." ', ' ".$f_name." ', '
".$l_name."
> >');";
> >
> >
> >but the statement itself shouldnt cause a problem either way.
> >
> >I am wondering where leads_id comes from however.. is it an auto number?
> >
> >
> >and finally your processing form is called addlead.php
> >and the form is posting to a form called addleads.php
> >
> >hope this helps
> >
> >chris
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